You are on page 1of 1

KHO ST CHT LNG LP 12, LN 1 - NM 2012

Mn: TON
Thi gian lm bi: 180 pht
PHN CHUNG CHO TT C TH SINH (7,0 im)
Cu I. (2,0 im) Cho hm s y = x 4 2mx 2 + 2m
1. Kho st hm s khi m = 1
2. Tm m hm s c 3 cc tr, 3 cc tr ny cng vi gc ta to thnh 1 t gic ni tip trong
mt ng trn

) cos( x + ) cos 2 (2 x + ) + 2 2 = 0
4
4
4
3
( x + 2) x + 1 = 8 y + 2 y

2.Gii h phng trnh


x + 1 + y 1 = 2

Cu II. (2,0 im) 1.Gii phng trnh 4 sin 3 x sin x + 4 cos(3 x

Cu III. (1,0 im) Tnh tch phn:

sin 4 x

(1 + cos x)(1 sin x) dx


0

Cu IV. (1,0 im) Cho hnh chp S.ABCD y l hnh thoi, AC = 2 3a , BD = 2a ,AC ct BD ti O.

(SAC) v (SBD) vung gc vi (ABCD).Bit khong cch t C n mt phng (SAB) l

a 3
Tnh th
2

tch S.ABCD v khong cch gia hai ng thng SC v BD.


Cu V. (1,0 im) Tm m phng trnh sau c hai nghim phn bit dng

x+

11
7

+ 4 1 + 2 =m
2x
x

PHN RING (3,0 im) Th sinh ch c lm mt trong hai phn (phn a hoc b)
a. Theo chng trnh Chun
Cu VIa. (2,0 im)
2
2
2
2
1. Trong mt phng Oxy cho ng trn (C ) x + y = 25 v ng trn (T): x + ( y 8) = 9 . Mt ng
thng (d) ct (C) ti A v B; ct (T) ti C v D tho mn AB=BC=CD. Vit phng trnh ng thng (d).
2. Trong khng gian Oxyz, cho mt phng (P): x y + z + 3 = 0 ,ng thng : ( ) :

x 3 y z +1
= =
v im
1
2
1

A(1,2,3) Vit ng thng d i qua A ,song song vi (P) v to vi () mt gc nh nht


Cu VIIa. (1,0 im):Gii phng trnh sau trn tp s phc: ( z 1) 2 ( z + 1) 2 + 9 z 2 = 0

b. Theo chng trnh Nng cao


Cu VIb. (2,0 im)
1. Cho im A(11,3), B (9,7) .Lp ng thng song song vi AB,ct ng trn ng knh AB ti C,D sao
cho C,D v hnh chiu ca chng ln ng thng AB l 4 nh mt hnh vung.
2. Cho im M(1,-1,0);A(1,1,0) v mt phng ( ) : 3 x + y + 2 = 0 .Vit phng trnh ng thng i qua
A,song song vi ( ) v khong cch t M n bng khong cch t n ( )
Cu VIIb. (1,0 im) Tm s phc z bit 2( z + 1) + z 1 = (1 i ) z

--------------------------------- Ht ------------------------------Ghi ch : K kho st cht lng ln 1 s c t chc vo ngy 28/5/2012.

You might also like