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Đề Cương Thu Phát Vô Tuyến
Đề Cương Thu Phát Vô Tuyến
CU 2:
Hai nh l ly mu:
+ nh l ly mu Shannon:
-
+ nh l Nyquist:
Nu : < th s xy ra hin tng xuyn bng. Xuyn bng c s dng t
c li ch trong cc ng dng ly mu di tn.
Phn tch ph ca tn hiu sau ly mu:
-
: ( )
k : s nguyn.
l tc ly mu.
Thng s l thuyt:
+ Trc tin, ta gi thit l ch c tp m do li lng t. Gi thit l bin ca tp
m lng t ny l mt bin ngu nhin phn b u trn mt bc lng t, gi thit
f
SNR 6, 02 N 1, 76 10 lg s dB
2 f max
y, fs l tn s ly mu, fmax l tn s cc i ca tn hiu tng t u vo. SNR
l thuyt bng 6dB thng c ni chnh l xp x ca phng trnh trn khi
fs=2fmax v b qua 1,76dB.
Thng s thc t:
+ Trong cc ADC thc t, SNR c th c xc nh bng cch o li d (Li d l
kt hp ca tp m lng t, tp m ngu nhin v mo phi tuyn).
+ Li d ca ADC c xc nh bng cch ly u ra ADC tr i c tnh tn hiu
u vo, kt qu l li d
+ SNR c tnh bng cch chia cng sut bnh phng trung bnh ca tn hiu u
vo cho cng sut trung bnh bnh phng ca li d.
CU 5:
Li d: l kt hp ca tp m lng t, tp m ngu nhin v mo phi tuyn (
ngha l tt c cc thnh phn khng mong mun ca tn hiu u ra ADC. c
xc nh bng cch s dng u vo dng sin cho ADC sau ly u ra ADC tr
i c tnh tn hiu u vo , tn hiu cn li l li d.
ENOD: S bit hiu dng l s bit cn thit trong mt ADC l tng cng sut
tp m trung bnh bnh phng trong ADC l tng ny bng cng sut trung bnh
bnh phng li d trong ADC thc t.
SFDR: Di ng khng c nhiu gi l mt thng s hu ch c t cc ADC.
Ga s u vo ADC l mt tone hm sin. SFDR c thc hin bng cch ly
FFT u ra ADC. Sau bin i ph u ra ADC c th hin dng cng sut
u ra dB ph thuc tn s. Khi ny SFDR s l hiu s gia tn hiu u vo hm
sin v cng sut nh ca tn hiu gi nhiu ln nht trong ph u ra ca ADC.
CU 6:
Thut ng v tuyn phn mm c s dng ni v mt my thu pht trong
cc thng s then cht c nh ngha trong phn mm v cc kha cnh c bn
CU 10: Kin trc BTS mi . Tch ring phn BBU v RFU, ni chung qua OBSAI
hoc CPRI. t RFU gn anten)
Tch ring phn s v phn v tuyn: S xut hin ca cc giao din chun
OBSAI v CPRI cng vi cc my pht thu RF u vo s dn n khng cn t
cc phn s v phn v tuyn gn nhau. My thu pht v tuyn c th c lp t
ti ti tr thun tin gn anten, chng hn trn tng ta nh hay trn nh ct
anten gim yu cu v cng sut v gim c gi thnh vn hnh cng nh v tr
lp t my.
Lp t trn thp anten: Lp t my thu pht RF trc tip trn thp cha cc
anten pht v thu (hnh a). Hin nay, lp t kiu ny kh ph bin cho cc mng
di ng 3G v 4G. N cho php loi b c tn hao ca cp v tuyn (gim 1
na, ~3dB)
D dng bo dng: t phn ln phn cng BTS ti mt v tr cho php thc hin
bo dng trung tm
D dng trin khai mng: D dng b sung mt site mi
RRH-Remote RF Head
y, mt giao din s c b sung h tr khong cch truyn dn xa hn s
vi yu cu ca mt ng dng trm gc thng thng. Giao din ny thng l
quang truyn c xa hn, tuy nhin cng c th s dng cp i dy xon hay
cp ng trc cho cc ng dng trong ta nh hay ngoi tri c khong cch ngn
hn.
CHNG 2
CU 13: Kin trc ca mt my thu n bng i tn:
My thu ngoi sai tng t:
CU 14: Tn s nh
Nguyn nhn:
+ Tn hiu RF ti u v tuyn thu l:
+
: tn s gc tn hiu hu ch.
: tn s gc tn hiu khng mong mun.
+ Tn hiu b dao ng ni LO
..
+
(
Kt qu: i= ..+
(
)+
(
)+.
)+
Nu
=
Th
Nu
=
Th
Trong
=2
v
=2
=
=
l tn s trung tn.
v
=
X l s vi thu IF s.
Nhiu bin i h tng vung gc c thc hin trong min s bng cch s
dng cc b dao ng c iu khin bng s NCO.
S dng lc thng thp cho cc tn hiu I v Q.
Nguyn l hot ng : Nhn hnh phn tch bnh thng.
CU 17: DC offset trong DCR:
Nguyn nhn:
+ Dch DC xut hin ti tm ca knh bng gc trong cc nhanh I v Q v mc dch
ny thng l kh cao so vi tn hiu cn gii iu ch.
+ Tn ti mt s ngun gy ra dch DC nh ngun li DC tnh, v ngun li DC
ng. Ngun li DC tnh xy ra do r tn hiu LO vo ca RF ca b trn v tn hiu
truyn lan phn x t cc phn t u thu ca my thu v quay tr li b trn, ti y
n trn vi chnh thnh phn mt chiu n. Ngun DC ng xy ra do s b tr
khng tng xng cc hiu ng thay i theo thi gian trong mt trng my thu nh
: cc phn x a phng ca LO my thu, s tng nhanh ca cng tn hiu gy
ra do fadinh Rayleigh lm cho mch AGC khng bm kp.
nh hng:
+ Lm gim nhy my thu.
+ Lm gim cp BER
CU 18: Cho mt tn s nhiu fn vo my thu khng i tn, chng minh bng do mo
hi bc 2 thnh phn ny s gy DC offset:
Da vo biu thc:
+ Tn hiu u vo. Lu pha ca tn hiu trong phng trnh 2.10 v 2.12 l :
(
)
+ T/thu c gm thnh phn mong mun v thnh phn 1 chiu v thnh phn
bc 2. Nu t/ u vo l mt nhiu ph lin tc th thnh phn mt chiu s gy ra
dch DC trm trng hn.
CU 19: Cc ng r trong DCR
, ta c th c tnh sai li
|
+ Ga tr in hnh: = 0.3 ,
th sai li l 1,5.
. Hu qu LO i hi
cc u ra I v Q c sai li bin v pha thp. Yu cu ny kh t c ti tn s
cao.
Bin php x l:
+ Li bin v pha c 2 thnh phn: tnh (khng thay i theo tn s) v ng. Nu
khng c b tr cc li ny s gy ra tn hiu nh trong bng khng mong mun
hay vecto tn hiu.
+ Trong trng hp tnh c th b tr liox ny bng cch lm mo trc cc tn
hiu I v Q hoc bn trong DSP hay bn ngoi trong phn cng tng t. C hai
dng b tr yu cu c cho trn hnh 2.18:
m ti tp m
Tn hiu ny ngoi t/h mong mun cn c thnh phn mt chiu v thnh phn
bc 2.
Gii thch tm tt hnh 2.19: R tn hiu pht vo my thu , t/h r ny cng vi
t/h thu ng thi c khuch i LNA v i qua b gii iu ch. Bng gc
ca t/h r v t/h thu c bn ct nhau ti mt mc gi li im ct bc 2 ca my
thu phi tuyn IP2. IP2 l mt thng s quan trng, n cho nh mo tnh phi
tuyn bc hai IMD2 v h tr nh lng nhy ca my thu i vi cc tn
hiu nhiu.
CU 25 : nh ngha IIP2 : C nh ngha ca IP2 ri . IP22 th sch ko vit nh.
Hot ng :
+ Tn hiu i vo b bin i h tn phi tuyn gm t/h mong mun v t/h li xut hin
ti u ra h thng.
+ Tn hiu li nhn c t hot ng phn hi thi gian thc v ng vai tr l tn
hiu lm mo trc b trn.
+ Qa trnh hnh thnh tn hiu li:
-
Nguyn tc:
+ u ra ca cc x l ni suy by gi c cp cho mt b bin i nng tn vung
gc s dng NCO lm tn hiu dao ng ni.
+ u ra ca b bin i nng tn c cp cho mt b DAC u ra IF v nu DAC
ny c ly mu qu tn th tc ly mu c th ln ti vi tram MHs
+ u ra DAC cha bng mong mun cng vi cc hi v sn phm xuyn bng. Cc
thnh phn gy nhiu ny c lc bi b lc bng thng (b lc SAW). Sau IF
c chuyn vo RF bng cch bin i nng tn.
Li im: S dng DAC hin i nhn c u ra ti mt tn s IF kh dng
(nhiu chc MHz). V th c th x l bin i nng tn vung gc trong min tn
s v loi b nh cng nh trit r LO hon ho.
Cu 34: B tch pha 900 s dng b lc thng cao v thng thp
1
1
1
ACLR ACS
CU36: Phng n BTS phn b (DBS), so snh gii php sd RF over Fiber v u ra
s.
Pr
vi 0 Pr2 1 , Pf , Pr l cng sut ca sng i
Pf
Ur
vi 0 Pr 1 , Uf , Ur l in p ca sng i thng
Uf
U max U f U r
U min U f U r
1
10lg 1 Pr2
2
1
Anten lng bng da trn hai anten Xpol (Xxpol) l mt h thng anten bao gm
mt anten Xpol vi cc kch thc chn t ln hn cho bng tn thp v mt h
thng anten Xpol c kch thc nh hn cho bng tn cao. C th phn loi theo
s u vo nh sau:
+ 4 u vo: cn 4 cp phido 4 cp nhy u ni (hnh a)
+ 2 u vo: Ch cn 2 cp phi v hai cp nhy cho u ni nhng phi c thm
b lc song cng (b kt hp) gn trm gc phn tch hai bng tn (hnh b)
gim bt s lng anten cho phn tp thu, cc bin php phn tp khng
gian sau y uc s dng:
S dng b lc song cng phn chia tn hiu pht thu t mt anten (hnh a)
Dng b chia tn hiu thu phn phi tn hiu thu t mt anten n nhiu my
thu (hnh b)
Cc s ny cho php gim s anten t 9 xung 6, nhng khng cho php gim
khong cch gia hai anten phn tp