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The Quantum Mechanics Solver 17


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- Section 16.2: Ramsey Fringes.
- The neutron spin precesses freely between the two cavities during time T , and we obtain.
- By definition, t 0 = t 1 +T and t 1 = 2t 1 − t 0 +T, therefore the transition matrix in the second cavity is.
- The probability amplitude for detecting the neutron in state.
- after the second cavity is obtained by (i) applying the matrix U to the vector (16.5), (ii) calculating the scalar product of the result with | n.
- Therefore, the probability that the neutron spin has flipped in the two-cavity system is.
- In contrast, the present result for two cavities exhibits a strong modulation of the spin flip probability, between 1 (e.g.
- This modulation results from an interference process of the two quantum paths corresponding respectively to:.
- a spin flip in the first cavity, and no flip in the second one,.
- no flip in the first cavity and a spin flip in the second one..
- Each of these paths has a probability 1/2, so that the sum of the probability amplitudes (16.6) is fully modulated..
- This form agrees with the observed variation in ω of the experimental signal..
- For that value, a constructive interference appears whatever the neutron velocity.
- (b) The angular frequency ω 0 is related to the magnetic moment of the neutron by ¯ hω 0 = 2µ n B 0 which leads to µ n J T − 1 .
- (c) This experiment can be compared to a Young double slit interference experiment with polychromatic light.The central fringe (corresponding to the peak at ω = ω 0 ) remains bright, but the contrast of the interferences de- creases rapidly as one departs from the center.
- The probability P.
- is the product of the two probabilities: the prob- ability to find the neutron in the state | n.
- when it leaves the first cavity (p = 1/2) and, knowing that it is in the state | n.
- the probability to find it in the same state when it leaves the second cavity (p = 1/2).
- 1/2 does not display any interference, since one has measured in which cavity the neutron spin has flipped.
- Section 16.3: Detection of the Neutron Spin State 16.3.1.
- Expanding in terms of the energy eigenstates, one obtains for | ψ(0).
- Physically, this means that the neutron’s spin state does not change since it is an eigenstate of ˆ V , while the atom’s spin precesses around the x axis with angular frequency A.
- The measurement of the z component of the atom’s spin gives.
- In both cases, after measuring the z component of the atom’s spin, the neutron spin state is known: it is the same as that of the measured atom.
- It is not necessary to let the neutron interact with another measuring apparatus in order to know the value of S nz.
- Section 16.4: A Quantum Eraser 16.4.1.
- Finally, when the neutron leaves the second cavity (step d), the state of the system is:.
- The probability to find the neutron in state.
- is the sum of the probabilities for finding:.
- (a) the neutron in state + and the atom in state.
- the square of the modulus of the coefficient of | n.
- There are no interferences since the quantum path leading in the end to a spin flip of the neutron can be determined from the state of the atom..
- h/2 along the y axis is the coefficient of the term | n.
- a : +y in the above expansion.
- Indeed the sum of the two probabilities calculated above is 1/2 as in 4.2.
- As seen in question 4.2, if the atom A is present, Bob no longer sees oscillations (in ω − ω 0 ) of the probability for detecting the neutron in the state.
- In the complementary set, where Alice has found.
- 2 can be interpreted as the interference of the amplitudes cor- responding to two quantum paths for the neutron spin which is initially in the state | n.
- either its spin flips in the first cavity, or it flips in the second one.
- After Alice has measured the atom’s spin along the y axis, she has, in some sense “restored” the initial state of the system, and this enables Bob to see some interferences.
- Notice that the statement in the text does not specify in which physical quantity the interferences appear.
- Notice also that the order of the measurements made by Alice and Bob has no importance, contrary to what this third statement seems to imply..
- Alice can measure along the axis w = sin η u y +cos η u z , in the (y, z) plane, for instance.
- For η = π/2 and 3π/2 or, more generally, if Alice measures in the (x, y) plane, the contrast of the interferences,.
- 16.6 Comments.
- The experimental curve given in the text is taken from J.H.
- One stores neutrons in a “bottle” for a time of the order of 100 s and applies two radiofrequency pulses at the begining and at the end of the storage.
- This improves enormously the accuracy of the frequency measure- ment.
- Such experiments are actually devised to measure the electric dipole moment of the neutron, of fundamental interest in relation to time-reversal.
- The structure of the inter- action Hamiltonian considered in the text has been chosen in order to provide a simple description of the quantum eraser effect.
- We study here the measurement of the cyclotron motion of an electron.
- The particle is confined in a Penning trap and it is coupled to the thermal radiation which causes quantum transitions of the system between various energy levels..
- This trap consists in the superposition of a uniform magnetic field B = B e z (B >.
- 17.1 The Penning Trap in Classical Mechanics.
- Show that the classical equation of motion of the electron in the trap is:.
- In order to study the component of the motion in the xy plane, we set α = x + iy..
- (b) We seek a solution of this equation of the form α(t.
- Show that ω is a solution of the equation:.
- Show that:.
- We consider the values B = 5.3 T and ω z /(2π.
- (a) Show that the most general motion of the electron in the Penning trap is the superposition of three harmonic oscillator motions..
- (c) Draw the projection on the xy plane of the classical trajectory of the trapped electron, assuming that α r α l (the positive quantities α r and α l represent the amplitudes of the motions of angular frequencies ω r and ω l.
- 17.2 The Penning Trap in Quantum Mechanics.
- We note ˆ r and ˆ p the position and momentum operators of the electron.
- The Hamiltonian of the electron in the Penning trap is, neglecting spin effects:.
- We are now interested in the motion along the z axis.
- (a) the expression of the operators ˆ a z and ˆ a † z which allow to write ˆ H z in the form ˆ H z.
- hω z ( ˆ N z + 1/2) with ˆ N z = ˆ a † z ˆ a z and [ˆ a z , ˆ a † z.
- We now consider the motion in the xy plane under the effect of the Hamiltonian ˆ H xy .
- (a) Show that [ˆ a r , ˆ a † r.
- (c) Recall the eigenvalues of ˆ n r = ˆ a † r ˆ a r and ˆ n l = ˆ a † l ˆ a l (no proof is required)..
- (d) Show that the Hamiltonian ˆ H xy can be written as:.
- (e) Deduce from this the eigenvalues of the Hamiltonian ˆ H xy.
- We note | ψ(t) the state of the system at time t and we define a r (t.
- Integrate these equations and calculate the expectation value of the elec- tron’s position ( x (t), y (t)) in the xy plane.
- Show that the time evolution of the expectation value of the electron po- sition r (t) is similar to the classical evolution found in Sect.
- We note | φ 0 the eigenstate of ˆ H corresponding to the eigenvalues 0 for each of the operators ˆ n r , ˆ n l and ˆ N z.
- (b) Using the same numerical values as in question 17.1.5, evaluate the spa- tial extension of φ 0 ( r.
- The experiment is performed at temperatures T ranging between 0.1 K and 4 K.
- Compare the characteristic thermal energy k B T to each of the energy quanta of the “cyclotron”, “axial” and “magnetron” motions (associ- ated respectively with ˆ n r , ˆ N z and ˆ n l.
- For which of these motions does the discrete nature of the energy spectrum play an important role?

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