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Lecture Mechanics of materials - Chapter Five: Torsion of Shafts

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Strain calculations: Figure 5.3 shows an approximate deformed shape of the two bars. The left end of the shaft is fixed into a rigid wall. We relate the shear strain in the bar to the rotation of the disc, as we did in Example 5.1.. We can then determine the sign of the shear strain using the definition of shear...

Lecture Mechanics of materials - Chapter One: Stress

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Weight of the Clothes Imaginary cut. Weight of the Clothes. Pull of the hand. Pull of the hand τ. of the Clothes. The diameter of the pin is 1 in. The area of the pin is . Figure P1.1. Figure P1.2. Figure P1.5. Figure P1.8. Board Figure P1.11. Figure P1.12. (Figure P1.17). Figure P1.14. Figure P1.15. Figure P1.16. Figure P1.17....

Lecture Mechanics of materials - Chapter 1: Stress

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August 2012 1-2. Normal Stress. All internal forces (and moments) in the book are in bold italics. Normal stress that pulls the surface away from the body is called a ten- sile stress.. Normal stress that pushes the surface into the body is called a com- pressive stress.. The normal stress acting in the direction of the axis of a...

Lecture Mechanics of materials - Chapter Two: Strain

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A C 6.25 mm 6.25 mm. 120.212 mm 0.019. AP 244.3188 mm 244.155 mm – 244.155 mm. 9.025 mm u C = 5.400 mm v C. 14.000 mm u G = 8.000 mm v G. 14.000 mm u H = 9.200 mm v H. Figure P2.1. Figure P2.2. Figure P2.3. 2.9 The average normal strain in bar A due to...

Lecture Mechanics of materials - Chapter 2: Strain

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1000 μ in / in is equal to a strain 0.001 in / in ε av L f – L o. C2.1 Due to the application of the forces in Fig. C2.1, the displace- ment of the rigid plates in the x direction were observed as given below.. 1.8 mm u C = 0.7 mm u D = 3.7 mm....

Lecture Mechanics of materials - Chapter Three: Mechanical Properties of Materials

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The deformation δ is movement of the two marks. Figure 3.4 Stress–strain curve.. C thus lies in the plastic region of the stress-strain curve, in which the material is deformed permanently, and the permanent strain at point F is the plastic strain. Starting from H we draw a line (HI) parallel to the linear part (OA) of the stress–strain curve....

Lecture Mechanics of materials - Chapter 3: Mechanical properties of materials

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August 2012 3-1. August 2012 3-3. The point up to which the stress and strain are linearly related is called the proportional limit.. The largest stress in the stress strain curve is called the ultimate stress.. The stress at the point of rupture is called the fracture or rupture stress.. The region of the stress-strain curve in which the material...

Lecture Mechanics of materials - Chapter Four: Axial members

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shown in Figure 4.3. (E1) (E2) For the homogeneous cross section the stress distribution is as given in Equation (E1), but for the laminated case it switches to Equation (E2), depending on the location of the point where the stress is being evaluated, as shown in Figure 4.6.. Figure P4.1. Figure P4.2. Figure P4.3. Figure P4.4. Figure P4.5. To obtain...

Lecture Mechanics of materials - Chapter 4: Axial members

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Develop the discipline to draw free body diagrams and approximate deformed shapes in the design and analysis of structures.. to obtain a formula for the relative displacements (u 2 -u 1 ) in terms of the internal axial force N.. to obtain a formula for the axial stress σ xx in terms of the internal axial force N.. The displacement...

Lecture Mechanics of materials - Chapter 5: Torsion of Shafts

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August 2012 5-1. Develop the discipline to visualize direction of torsional shear stress and the surface on which it acts.. C5.1 Three pairs of bars are symmetrically attached to rigid discs at the radii shown. and in the direction of the applied torques T 1 , T 2 , and T 3 respectively. The shear modulus of the bars is...

Lecture Mechanics of materials - Chapter Six: Symmetric bending of beams

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Draw the free-body diagram of the rigid plate and determine the moment M ext. External moment calculations: Figure 6.7 is the free body diagram of the rigid plate. Equations (6.1) and (6.2) are independent of the material model. 0.5 in 0.5 in. 6.6 The rigid plate shown in Figure P6.6 was observed to rotate 1.25 ° from the vertical plane...

Lecture Mechanics of materials - Chapter 6: Symmetric bending of beams

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C6.1 Due to the action of the external moment M ext and force P, the rigid plate shown in Fig. C6.1 was observed to rotate by 2 o from the ver- tical plane in the direction of the moment. Both bars have an area of cross-section of A = 1/2 in 2 and a modulus of elasticity of E =...

Lecture Mechanics of materials - Chapter Seven: Deflection of symmetric beams

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For the beam and loading shown in Figure 7.7, determine: (a) the equation of the elastic curve in terms of E, I, L, P, and x. Write the boundary-value problem for solving the deflection at any point x of the beam shown in Figure 7.9. 7.1 For the beam shown in Figure P7.1, determine in terms of P, L, E,...

Lecture Mechanics of materials - Chapter 7: Deflection of symmetric beams

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ble/MoM2nd.htm. Deflection of Symmetric Beams. Learn to formulate and solve the boundary-value problem for the deflection of a beam at any point.. August 2012 7-2. Printed from: http://www.me.mtu.edu/~mavable/MoM2nd.htm. Second-Order Boundary Value Problem. The deflected curve represented by v(x) is called the Elastic Curve.. The mathematical statement listing all the differential equations and all the conditions necessary for solving for v(x)...

Lecture Mechanics of materials - Chapter Eight: Stress transformation

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Figure 8.1 Failure surfaces. Determine the normal and shear stress on the plane containing the weld line.. Step 1 of the procedure outlined in Section 8.1.1 is complete, as shown in Figure 8.3. Step 2: We construct a wedge from the horizontal, vertical, and inclined plane, as shown in Figure 8.4a. These forces are shown on the force wedge in...

Lecture Mechanics of materials - Chapter 8: Stress transformation

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Develop the ability to visualize planes passing through a point on which stresses are given or are being found, particularly the planes of maximum normal stress and maximum shear stress.. The fixed reference coordinate system in which the entire problem is described is called the global coordinate system.. A coordinate system that can be fixed at any point on the...

Lecture Mechanics of materials - Chapter Nine: Strain transformation

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Figure 9.1 Measurement of strains using strain gages. Step 1: View the axes of the n, t coordinate system as two lines, as shown in Figure 9.3a. Due to the normal strain in the x direction, the lines in the n and t directions deform to n 1 and t 1 , as shown in Figure 9.3a.. Calculations in the...

Lecture Mechanics of materials - Chapter 9: Strain transformation

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August 2012 9-1. Learn the equations and procedures of relating strains at a point in dif- ferent coordinate systems.. Global coordinate system is x,y, and z.. Local coordinate system is n, t, and z.. We assume ε xx , ε yy , and γ xy are known at a point.. Step 2 Construct a rectangle with a diagonal in direction...

Lecture Mechanics of materials - Chapter Ten: Design and failure

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10.1 COMBINED LOADING. Figure 10.1 Examples of combined loadings.. z axis (10.3a). (10.3b). y axis (10.4a). (10.4b) σ xx N. Figure 10.2 Thin hollow cylinder. 10.1.1 Combined Axial and Torsional Loading. Figure 10.3 Stresses due to (a) axial loading. Figure 10.4 Stresses in combined axial and torsional loading.. 10.1.3 Extension to Symmetric Bending about y Axis. Figure 10.5 Stresses due...

Lecture Mechanics of materials - Chapter 10: Design and failure

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about z-axis. about y-axis. Combined Axial, Torsional and Bending about z-axis. Bending about z-axis. Bending about y-axis. The complexity of finding the state of stress under combined loading can be simplified by first determining the state of stress due to individ- ual loading.. In order to use subscripts to determine the direction (sign) of stress components, a local x, y,...