Có 60+ tài liệu thuộc chủ đề "Physics"
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25.1: Q It. 89 10 4 C.. 25.2: a) Current is given by I Q t C s. 25.4: The cross-sectional area of the wire is. 25.5: J n q v d , so J v d is constant.. 25.6: The atomic weight of copper is 63 . 25.1), The number of free electrons per copper...
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26.1: a) 12 . 26.3: For resistors in series, the currents are the same and the voltages add. 26.4: a) False, current divides at junction a.. 26.6: a) R eq. 26.10: a) The three resistors R 2 , R 3 and R 4 are in parallel, so:. 26.11: Using the same circuit as in Problem 27.10, with all resistances the...
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ˆ s m 10 3.85 T)[(. 1 s m 10 C)(4.00 10. ˆ ) T)( ˆ )(1.63 s m 10 C)(3.0 10. 10 (9.11. T) 10 )(7.4 s m 10 C)(2.50 10. 60 sin ) T 10 C)(3.5 10. 49 10 6 m s. 27.8: a) F q v B qB z [ v x (...
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28.1: For a charge with velocity v. T 10 1.92 ˆ. T 10 ) 1.31. s m 10 6.80. C 10 4.80. T 10 4.62. T 10 1.31. 28.4: a) Following Example 28.1 we can find the magnetic force between the charges:. m 10 9.00. s m 10 4.50. C 10 3.00. C 10 8.00. C m N 10 8.99....
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29.2: a) Before. 29.4: From Exercise (29.3),. 29.5: From Exercise (29.3),. 29.7: a) 2 for 2 sin. ind d dt B dt d ( B 1 A. 29.9: a) c 2 r and A. dt c dc π B dt. 29.10: According to Faraday’s law (assuming that the area vector points in the positive z-...
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30.2: For a toroidal solenoid, 2 / 1 , and B . 25 / H) 10 (6.82 A) 20 . 30.5: 1 H 1 Wb / A 1 Tm 2 / A 1 Nm / A 2 1 J / A 2 1 (J / AC)s 1 (V / A)s 1 Ωs.. 30.6:...
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31.1: a) 31 . 31.2: a) I 2 I rms 2 ( 2 . 31.5: a) X L ωL 2 πfL 2 π ( 80 Hz. 31.6: a) X L ωL 2 πfL 2 π ( 60 Hz)(0.450 H. 31.10: a) 1736. 31.11: a) If 1 1 1 0. 31.12: a) Z...
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10 8.16 m. 10 8.16 s) 10 (2.72 s) m 10 0 . 32.3: B ) max cos( ˆ j max cos 2. 28 10 7 m 1 ) z. 83 10 15 rad s ) t ) ˆ j . 74 10 5 V m) cos. 83 10 15 rad s) t) i .ˆ....
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m/s 10 1.94. 33.4: 1.501. m/s 1 10 2.17. 33.7: n a sin a n b sin b. 33.9: a) Let the light initially be in the material with refractive index n a and let the third and final slab have refractive index n b Let the middle slab have refractive index n 1. 1 1 sin...
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34.2: Using similar triangles,. 34.4: a) 17 . cm) .60 6 cm. 34.11: a). 34.12: a). 34.13: a). cm cm) 5.45. 34.14: a) 4 . 34.15: 1 . 34.16: a) 1 . 34.18: a) 8 . 34.19. 34.20: 14 . 34.21: 8 . 34.22: a) 14 . 34.24: a) 48 . 16.0 12.0) cm). 34.25: 3 . 34.26: 0 ....
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35.1: Measuring with a ruler from both S 1 and S 2 to there different points in the. 35.2: a) At S 1 , r 2 r 1 4 λ , and this path difference stays the same all along the axis,. 35.3: a) For constructive interference the path diference is m λ , n 0. 35.4:...
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m) 10 (7.50 m) 10 (1.35. m) 10 (5.46 m) (0.600 λ. 36.3: The angle to the first dark fringe is simply:. m 10 0.24. m 10 7.50. m) 10 (6.33 m) 2(3.50 λ. 36.5: The angle to the first minimum is. 36.6: a) According to Eq. 36.7: The diffraction minima are located by sin. 36.8: a) E E...
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00 10 8 m s. s m 10 2(3.00. 00 10 8 m s s. m 10 3.00. (37.7) for. 37.10: a) 1.51 10 s.. 37.11: a) l 0 3600 m. s m 10 4.00. 37.12: γ 1 0 . 37.13:. 37.15: a) c c c. 37.16: γ 1 . (37.6), so. 00 10...
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10 5.20. s m 10 3.00 λ. 10 3.84. s m kg 10 m 1.28. s J 10 6.63 λ. 94 10 16 . s J 10 6.63. Hz 10 5.91. J 10 3.04. eV J 10 (1.60 eV) m (5.1. 10 s 2.35. J 10 (6.63. kg 10 9.11. J 10 1.6 J 1eV 10. 38.10: K max...
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39.5: a) In the Bohr model . 39.6: a) For a nonrelativistic particle. 39.8: Combining Equations 37.38 and 37.39 gives p mc γ 2 1 . 39.9: a) photon. 39.10:. 39.11: a) λ 0 . 39.12: (a) λ h mv v h m λ Energy conservation: e V 2 1 mv 2....
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40.1: a m) kg)(1.5 20. 22 10 J) 3.7 10 J.. kg)(5.0 10. 10 8(9.11 s) 3. 40.4: a) The energy of the given photon is. m/s) 10 (3.00 s) J 10 63 . 40.5: E 2 1 mv . 5 10 7 J gives L 6 . 40.6: a) The wave function for n ...
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s J 10 4.716. 41.2: a) 2 , so 2. 41.4: The ( l , m l ) combinations are . 41.6: a) As in Example 41.3, the probability is. For 2 1 transition, the coefficient is eV)=10.19 eV.. and the 2 1 transition gives (10.19 eV eV.. 41.9: a) 31 19 2. 41.10: e im l....
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42.3: Let 1 refer to C and 2 to O.. 42.4: The energy of the emitted photon is 1 . 42.5: a) From Example 42.2,. 674 10 J and I 1 . 449 10 kg m E. 03 10 12 rad s. 42.7 the spacing between adjacent vibrational energy levels is twice the...
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43.2: a) Using R. 43.4: a) As in Example 43.2,. 511 10 6 eV. 43.7: The binding energy of a deuteron is 2 . 224 10 6 eV. 43.9: a) For 11 5 B the mass defect is:. (43.11):. 43.10: a) 34 m n 29 m H m Cu u u u u and. 43.11:...
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The wavelength calculated in Example 44.1 is 2.43 pm. 44.2: The total energy of the positron is. 00 MeV 0.511 MeV 5.51 MeV.. 44.3: Each photon gets half of the energy of the pion. s m 10 (3.00 kg . 44.6: a) The energy will be the proton rest energy, 938.3 MeV, corresponding to a frequency of 2...