Có 20+ tài liệu thuộc chủ đề "Thermochemistry"
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3.3.2 Deflagration Wave 51 3.4 Ignition Reactions 53 3.4.1 The Ignition Process 53 3.4.2 Thermal Theory of Ignition 53 3.4.3 Flammability Limit 54. The combustion wave structures and the heat feedback processes from the gas phase to the condensed phase are also discussed to aid in the understanding of the relevant combustion mechanisms. Though the form of the Rankine−Hugoniot equation,...
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Remember that the base units of the joule are. We will need to know the mass of the atom in kilograms.. We can write Equation 5.2 for each case and di v id e one by the other to determine the relative magnitudes of the results.. The calorie is defined in terms of the joule:. where Vi and Vr are...
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The final temperature of the sys te m was found to be 28.4 °C. Calculate the specific he at of the metal. (The heat capacity of the calori meter is 12.4 We.). What i s the final temperature of the combined wate r. to vapo rize 1.00 g of the liquid at its boiling point. nitroge n if the final...
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The electrons in the other half of the atoms will be spin. and orientation (m e) of the orbital. 1 Which of the following is a legitimate 6.6.3. He made important co ntributions to the study of the magnetic prope rtie s of at oms and the kinetic th eory of gases. For any value of the principal quantum number...
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zinc (Zn), iodine (I), cobalt (Co), selenium (Se), and fluorine (F), which together make up about 0.1 percent of the body 's ma ss . Checkpoint 7.1 Development of the Periodic Table. 7.1.1 Which of the following elements would you expect to have chemical properties most similar to tho se of S?. Which of the following elements would you expect...
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The first two oxides of the third period, Na20 and MgO, are basic oxides. The intermediate properties of the oxides (as demonstrated by the amphoteric oxides) are exhibited by elements whose positions are intermediate within the period. one of the phases of what is known today as bipolar disorder. d) Write the electron configuration for each of the alkali metal...
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o Half of the atom ' s bonding electrons are a ss ociated with the atom.. As with oxidation numbers, the sum of the formal charg e s mus t equal the overall c harge on the species [I~~ Section 4.4]. In th e 0 3 molecule , for example , there is no evidence that the central atom bears...
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All po sitions are equiv alent in the octahedral geometry, so one lone pair on the central atom can occupy any of the po sition s . Draw the Lewis structure of the molecule or polyatomic ion.. Determine the molecular geometry by considering the positions of the atoms only.. Two lone pairs on an octahedron will be located on oppo...
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We can do similar analyses of the molecules Li2 and Bez. Figure 9 .16(b) shows the locations of the molecular orbitals resulting from the combination of P Y ' and p z orbitals relative to the two atomic nuclei. To understand better the relative energy levels of the molecular orbitals resulting from p-orbital combinations, consider the fluorine molecule (F z)....
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11.7(a) 11.7(b) 11.7(c). If, for example, as s hown in Figure 11.7(b), we double the pressure on the confined gas by adding enough mercury to make the difference in mercury levels on the left and right 760 mm (the height of a mercury column that exerts a pressure equal to 1 atm), the volume of the gas i s reduced...
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Sample Problem 11.12]. 11.2 PYI = P z V 2 (at constant temperature). 11.3 (a ) V = k2T (at constant pre ss ure) 11.3 (b). 11.10. 11.15. 11.16. Section 11.1: Properties of Gases. 11.2 11.3. 11.11 Why is it that if the barometer reading falls in one part of the world, it mu s t ri se so mewhere...
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Figure 12.15 Arrangement of identical spheres in a simple cubic cell. Figure 12.16 Three types of cubic cells. The other types of cubic cells, shown in Figure 12.16, are the body-centered cubic cell (bcc) and the face-centered cubic cell (fcc). SECTION 12.3 Crystal Structure 475. Figure 12.18 (a) A comer atom in any cell is shared by eight unit cells....
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12.99 Which of the following properties indicates ve ry s tron g. 12.103 Which of the following sub s tances h as the highest polarizability:. 12.105. 12.106. 12.107. 12.108. 12.109. 12.110. 12.111. 12.115. 12.116. 12.117. 12 .11 8. 12.119. 12.120. effect on the vapor pre ssu re of the water w he n (a) it s temperature is lowere d,...
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Checkpoint 13.5 Colligative Properties. SECTION 13.6 Calculations Using Colligative Properties 527. Sample Problems 13.10 and 13.11 illustrate this technique.. Sample Problem 13.10. Strategy Use Equation 13.7 to determine the molal concentration of the solution. Solution Solving Equation 13.7 for molal concentration,. Strategy Use Equation 13.8 to calculate the molarity of the solution. Solution Rearranging Equation 13.8 to solve for molarity,...
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[F, I doubles 0.10 0.20. Rate doubles 4.8 X X 10 - 3. rate 3 2.4 X 10 - 3 Mis = 2. rate I 1.2 X 10 - 3 Mis. 4.8 X 10 - 2.4 X 10 - 3. Thus, we can write the rate law as follow s. k = rate 1.2 X 10 - 3 Mis =...
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e) Calculate t ll2 of the reaction. 14.1 14. 14.4 14.5. 14.10. 14.11. Section 14.1: Reaction Rates Review Questions. 14.1 What is meant by the rate of a chemical reaction ? What are the units of the rate of a reaction. 14.3 What are the advantages of measuring the initial rate of a reaction?. 14.7 Consider the reaction. 14.8 Consider...
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which has an equilibrium constant (Ke) of 3 .0 X 10 - 6 at ns o c.. a) 3.0 X 10 - 6 c ) 2.0 X 10- 2 b) 2.5 X 10 - 4 d ) 3 . it) 3.0 X 10 - 6 atm b) 3.3 X 10 5 atm. lS.4A (a) 2.3 X 10 24 , (b)...
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Sample Problem 16.16. Checkpoint 16.7 Conjugate Acid-Base Pairs. Checkpoint 16.8 Diprotic and Polyprotic Acids. Figure 16.3 Lewis structures of the oxoacids of chlorine. SECTION 16.10 Acid-Base Properties of Salt Solutions 663. Sample Problem 16.20. 16.7 to determine Ka for NH t. SECTION 16.10 Acid-Base Properties of Salt Solutions 665. Figure 16.4 The six H 2 0. Checkpoint 16.10 Acid-Base Properties...
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Consider a liter of solution containing 0.10 mole of acetic acid. Using the Kafor acetic acid (1.8 X 10- 5 ) and an equilibrium table. Initial co ncentration (M): 0.10 0 0. Equilibrium concentration (M): 0.10 - x x x. Assuming that (0.10 - x) M = 0.10 M and solving for x, we get 1.34 X 10 - 3...
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Sample Problem 17.11. (Figur e 17.10):. Figure 17.9 (Left)Anaqueous cobalt(II) chloride solution. Checkpoint 17.5 Factors Affecting Soubility. Sample Problem 17.12. Fig u re 17.11 Flame tests for. Checkpoint 17.6 Separation of Ions Using Differences in Solubility. 17.6.1 A solution is 0.10 M in Br. 17.6.2 Barium nitrate is added slowly to a solution that is 0 . Figure 17.12 A...